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Question: Answered & Verified by Expert
0.005 mol of Ba OH 2   is dissolved in 100 mL of water. Assuming complete ionisation of Ba OH 2 the pOH of the solution will be
ChemistryIonic EquilibriumNEET
Options:
  • A 1
  • B 5
  • C 2
  • D 14
Solution:
1291 Upvotes Verified Answer
The correct answer is: 1
100 mL of solution contain 0.005 moles of Ba OH 2  

1 1000 mL of solution contain

= 10×0.005 mole of Ba OH 2

Concentration of Ba OH 2 (i.e. moles on litres)

=  0.05 M

Each Ba OH 2 give 2OH ions

Thus, moles of OH per L =2×0.05=0.1

iii pOH=log OH

pOH=log 0.1 = log10 1

pOH=log10=1

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