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$0.45 \mathrm{~g}$ of acid molecular weight 90 is neutralised by $20 \mathrm{ml}$ of $0.5 \mathrm{~N}$ caustic potash. The basicity of acid is
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The correct answer is:
2
Eq. of acid = Eq of base,
$\begin{array}{l}
\therefore \frac{0.45}{\mathrm{E} \cdot \mathrm{wt}}=\frac{20 \times 0.5}{1000}=\mathrm{E} \mathrm{wt}=45 \\
\text { Basicity }=\frac{\mathrm{M} \cdot \mathrm{wt}}{\mathrm{E} \cdot \mathrm{wt}}=\frac{90}{45}=2
\end{array}$
$\begin{array}{l}
\therefore \frac{0.45}{\mathrm{E} \cdot \mathrm{wt}}=\frac{20 \times 0.5}{1000}=\mathrm{E} \mathrm{wt}=45 \\
\text { Basicity }=\frac{\mathrm{M} \cdot \mathrm{wt}}{\mathrm{E} \cdot \mathrm{wt}}=\frac{90}{45}=2
\end{array}$
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