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Question: Answered & Verified by Expert
0.6g of a solute is dissolved in 0.1 litre of a solvent which develops an osmotic pressure of $1.23 \mathrm{~atm}$ at $27^{\circ} \mathrm{C}$. The molecular mass of the substance is
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Options:
  • A $149.5 \mathrm{gmole}^{-1}$
  • B $120 \mathrm{gmole}^{-1}$
  • C $430 \mathrm{~g} \mathrm{~mole}^{-1}$
  • D None of these
Solution:
1430 Upvotes Verified Answer
The correct answer is: $120 \mathrm{gmole}^{-1}$
$m=\frac{w R T}{P V}=\frac{0.6 \times 0.082 \times 300}{1.23 \times 0.1}=120 \mathrm{gmole}^{-1}$

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