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Question: Answered & Verified by Expert
$1-2 \sin ^2\left(\frac{\pi}{4}+\theta\right)=$
MathematicsTrigonometric Ratios & IdentitiesJEE Main
Options:
  • A $\cos 2 \theta$
  • B $-\cos 2 \theta$
  • C $\sin 2 \theta$
  • D $-\sin 2 \theta$
Solution:
1010 Upvotes Verified Answer
The correct answer is: $-\sin 2 \theta$
$1-2 \sin ^2\left(\frac{\pi}{4}+\theta\right)=\cos \left(\frac{\pi}{2}+2 \theta\right)=-\sin 2 \theta$

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