1 g of 79 Au 198 t 1/2 =65 h give stable mercury by β - emission. What amount of mercury will left after 260 h?

Question

1 g of 79 Au 198 t 1/2 =65 h give stable mercury by β - emission. What amount of mercury will left after 260 h?, 0.9375 g, 0.3758 g, 0.7586 g, 0.9000 g

MARKS App · Accepted Answer

79 A u 198 → - B 80 H g 198 k = 0 .693 t 1/2 = 0 .693 65 After 260 hr, k = 2 .303 260 log a a − x 0 .693 65 = 2 .303 260 log a a − x a a − x = 16 1 1 − x = 16 x = 15 16 g = 0 .9375 g

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