1 g of Au 79 198 t 1 2 = 65 h decays by Beta emission and produce stable mercury. How much mercury will be present after 260 h.

Question

1 g of Au 79 198 t 1 2 = 65 h decays by Beta emission and produce stable mercury. How much mercury will be present after 260 h., 0.93 g, 0.85 g, 1 g, 0.79 g

MARKS App · Accepted Answer

A u 19 198 → H g 80 108 + θ - 1 0 t 1 2 = 65 h T = 260 h T = t 1 2 × ′ n ′ Number of Lay live (n) = 260 65 = 4 Amount of undecayed A u = N 0 2 n = 1 2 4 = 1 16 g Amount of decayed Au = 1 - 1 16 = 15 16 = 0 .93 g

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