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$1 \mathrm{~g}$ of silver gets distributed between $10 \mathrm{~cm}^{3}$ of molten zinc and $100 \mathrm{~cm}^{3}$ of molten lead at $800^{\circ} \mathrm{C}$. The percentage of silver in the zinc layer is approximately
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The correct answer is:
97
Concentration of Ag in zinc $=\frac{x}{10}$
$\therefore$ Concentration of $\mathrm{Ag}$ in $\mathrm{Pb}=\frac{1-\mathrm{x}}{100}$
$$
\frac{\frac{x}{10}}{\frac{1-x}{100}}=300
$$
On solving, we get $\mathrm{x}=97 \%$
$\therefore$ Concentration of $\mathrm{Ag}$ in $\mathrm{Pb}=\frac{1-\mathrm{x}}{100}$
$$
\frac{\frac{x}{10}}{\frac{1-x}{100}}=300
$$
On solving, we get $\mathrm{x}=97 \%$
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