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$\left\{\frac{2 i}{1+i}\right\}^2=$
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The correct answer is:
$2 i$
$\left[\frac{2 i}{1+i}\right]^2=\left[\left(\frac{2 i}{1+i}\right)\left(\frac{1-i}{1-i}\right)\right]^2=(i+1)^2=i^2+1+2 i=2 i$
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