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$1 \mathrm{M}$ and 2.5 litre $\mathrm{NaOH}$ solution is mixed with another $0.5 \mathrm{M}$ and 3 litre $\mathrm{NaOH}$ solution, then molarity of the resultant solution will be
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The correct answer is:
$0.73 \mathrm{M}$
$\begin{aligned} & (2.5 \times 1+3 \times 0.5)=M_3 \times 5.5 \\ & \text { or } 2.5+1.5=M_3 \times 5.5 \text { or } M_3=\frac{4}{5.5}=0.73 M \text {. } \\ & \end{aligned}$
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