1 mol of A g I / A g + is coagulated by

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Question: Answered & Verified by Expert

1 mol of

A g I / A g^{+}

is coagulated by

ChemistrySurface ChemistryNEET

Options:

A $1 mol$ of $KI$
B $500 mL$ of $1 M K_{2} {SO}_{4}$
C $300 mL$ of $1 M {Na}_{3} {PO}_{4}$
D $1 mol$ of $AgI$

Solution:

1153 Upvotes Verified Answer

The correct answer is:

1 mol

of

KI

1 mol of

A g I / A g^{+}

is coagulated by 1 mol of KI. Here 1 mol

A g^{+}

will combine with 1 mol

I^{-}

to form precipitate of 1 mol

AgI

.

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