Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
1 mole of photon, each of frequency $2500 \mathrm{~S}^{-1}$, would have approximately a total energy of:
ChemistryStructure of AtomJEE Main
Options:
  • A $1 \mathrm{erg}$
  • B 1 Joule
  • C $1 \mathrm{eV}$
  • D $1 \mathrm{MeV}$
Solution:
2777 Upvotes Verified Answer
The correct answer is: $1 \mathrm{erg}$
Total Energy $=\mathrm{Nhv}=6.022 \times 10^{23} \times 6.626 \times 10^{-34} \mathrm{~J} . \mathrm{S} . \times 2500 \mathrm{~s}^{-1}=9.9 \mathrm{erg} \approx 10 \mathrm{erg}$ In (A) option, it should be 10 erg instead of $1 \mathrm{erg}$.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.