10 . 0 mL of 0 . 05 M KMnO 4 solution was consumed in a titration with 10 . 0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is ........ × 10 - 2 g / L . (Round off to the nearest integer)

Question

10 . 0 mL of 0 . 05 M KMnO 4 solution was consumed in a titration with 10 . 0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is ........ × 10 - 2 g / L . (Round off to the nearest integer),

MARKS App · Accepted Answer

n eq KMnO 4 = n eq H 2 C 2 O 4 · 2 H 2 O or, 10 × 0 . 05 1000 × 5 = 10 × M 1000 × 2 ∴ Conc. of oxalic acid solution = 0 . 125 M = 0 . 125 × 126 g / L = 15 . 75 g / L = 1575 × 10 - 2 g / L

Search any question & find its solution

Looking for more such questions to practice?