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\( 10 \mathrm{~g} \) of a mixture of \( \mathrm{BaO} \) and \( \mathrm{CaO} \) requires \( 100 \mathrm{~cm}^{3} \) of \( 2.5 \mathrm{M} \mathrm{HCl} \) to react completely. The
percentage of calcium oxide in the mixture is approximately
(Given : molar mass of \( \mathrm{BaO}=153 \) )
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percentage of calcium oxide in the mixture is approximately
(Given : molar mass of \( \mathrm{BaO}=153 \) )
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2070 Upvotes
Verified Answer
The correct answer is:
\( 52.6 \)
For the completely neutralization reaction,
Let the mass of \( \mathrm{CaO} \) in mixture is \( x \mathrm{~g} \) and that of BaO is \( 10-x g \)
Now, The sum of the gram equivalents of \( \mathrm{CaO} \) and \( \mathrm{BaO} \)
\[
\begin{array}{l}
=\frac{100 \times 2.5}{1000}=0.2 \\
\Rightarrow \frac{x}{28}+\frac{10-x}{76.5}=0.25 \\
\Rightarrow \frac{76.5 x+280-28 x}{28 \times 76.5}=0.25 \\
\Rightarrow 48.5 x=(0.25 \times 25 \times 76.5)-280 \\
\Rightarrow x=\frac{255.5}{48.5}=5.26
\end{array}
\]
Percentage of \( \mathrm{CaO} \) in mixture is \( =\frac{5.26}{10} \times 100=52.6 \% \)
Let the mass of \( \mathrm{CaO} \) in mixture is \( x \mathrm{~g} \) and that of BaO is \( 10-x g \)
Now, The sum of the gram equivalents of \( \mathrm{CaO} \) and \( \mathrm{BaO} \)
\[
\begin{array}{l}
=\frac{100 \times 2.5}{1000}=0.2 \\
\Rightarrow \frac{x}{28}+\frac{10-x}{76.5}=0.25 \\
\Rightarrow \frac{76.5 x+280-28 x}{28 \times 76.5}=0.25 \\
\Rightarrow 48.5 x=(0.25 \times 25 \times 76.5)-280 \\
\Rightarrow x=\frac{255.5}{48.5}=5.26
\end{array}
\]
Percentage of \( \mathrm{CaO} \) in mixture is \( =\frac{5.26}{10} \times 100=52.6 \% \)
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