Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
10 moles of A2 , 15 moles of B2 and 5 moles of AB are placed in a 2 litre vessel and allowed the come to equilibrium. The final concentration of AB is 10.5 M ,

A 2 g + B 2 g 2AB g

Determine the value of equilibrium constant KC for the reaction.
ChemistryChemical EquilibriumJEE Main
Options:
  • A 25.3
  • B 31.5 
  • C 36.3
  • D 40.5
Solution:
2286 Upvotes Verified Answer
The correct answer is: 31.5 


5+2x2=10.5 ;x=8

KC=[AB]2A2B2=5+2x2210-x215-x2=(21)22×7=31.5

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.