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Question: Answered & Verified by Expert
\(10^n+3\left(4^{n+2}\right)+5\) is divisible by \((n \in N)\)
MathematicsQuadratic EquationBITSATBITSAT 2009
Options:
  • A 7
  • B 5
  • C 9
  • D 17
Solution:
1373 Upvotes Verified Answer
The correct answer is: 9
\(\begin{aligned}
& 10^n+3\left(4^{n+2}\right)+5 \text { Taking } n=2, \\
& 10^2+3 \times 4^4+5=100+768+5=873
\end{aligned}\)
Therefore this is divisible by 9.

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