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${ }_{11} Na $^{24}$ is radioactive and it decays to
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${ }_{12} \mathrm{Mg}^{24}$ and $\beta$ - particles
$_{11} \mathrm{Na}^{24} \longrightarrow _{12} \mathrm{Mg}^{24}+_{-1}\beta^{0}$
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