1.22 g C 6 H 5 COOH is added into the 100 g solvent CH 3 COCH 3 where data of Δ T b and K b are given as: ΔT b = 0.17, solute by K b = 1.7 K kg/mol Find out the molecular weight (g/mol) of the solute in the solution by interpreting the result.

Question

1.22 g C 6 H 5 COOH is added into the 100 g solvent CH 3 COCH 3 where data of Δ T b and K b are given as: ΔT b = 0.17, solute by K b = 1.7 K kg/mol Find out the molecular weight (g/mol) of the solute in the solution by interpreting the result.,

MARKS App · Accepted Answer

Δ T b = 0.17 = K b · m 0.17 = 1.7 × 1.22/M 100/1000 M = 122 g/mole Benzoic acid is not associated or dissociated.

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