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Question: Answered & Verified by Expert
1.5 gm sample of bleaching powder was suspended in water. It was treated with CH3COOH followed by the addition of excess of KI. The liberated iodine required 150 mL of M10 hypo solution for complete titration. The percentage of available chlorine in the sample is
ChemistryRedox ReactionsJEE Main
Solution:
1962 Upvotes Verified Answer
The correct answer is: 35.5
2KI+Cl22KCl+I2

I2+2S2O32-2I-+S4O62-

Mol of available Cl2 mole of iodine

=1×150×10-310×2

Amount of available Cl2

=150×10-320×71g

% of available Cl2

=150×10-3×71×10020×1.5=35.5

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