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Question: Answered & Verified by Expert
$16 \mathrm{~g}$ each of $\mathrm{H}_2$, He and $\mathrm{O}_2$ are present in a container exerting $10 \mathrm{~atm}$. pressure at $T(\mathrm{~K})$. The pressure in atm exerted by $16 \mathrm{~g}$ each of $\mathrm{He}$ and $\mathrm{O}_2$ in the second container of same volume and temperature is
ChemistryStates of MatterAP EAMCETAP EAMCET 2018 (22 Apr Shift 1)
Options:
  • A 1.8
  • B 6.4
  • C 3.6
  • D 5.4
Solution:
1398 Upvotes Verified Answer
The correct answer is: 3.6
Mixture of $\mathrm{H}_2$, He and $\mathrm{O}_2 16 \mathrm{~g}$ each exert $=10$ atm pressure.
Mixture of $\mathrm{He}, \mathrm{O}_2$ exert ( $16 \mathrm{~g}$ each) pressure $=$ ?
Mixture of $36 \mathrm{~g}$ exert pressure $=\frac{36}{10}=3.6$

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