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Question: Answered & Verified by Expert
-π2π2log2-sin x2+sin xdx= 
MathematicsDefinite IntegrationMHT CETMHT CET 2016
Options:
  • A 1
  • B 3
  • C 2
  • D 0
Solution:
1381 Upvotes Verified Answer
The correct answer is: 0
Let I=-π2π2log 2-sin x2+sin xdx
As given function f( x )=log( 2sinx 2+sinx ) is odd.
I= f( x )dx=0

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