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$2 \mathrm{CH}_3 \mathrm{COOH} \xrightarrow{-\mathrm{MeO} \mathrm{C}} A$, product ' $A$ ' in the reaction is
Options:
- A $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CHO}$
- B $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{OH}$
- C $\mathrm{CH}_3 \mathrm{COCH}_3$
- D
Solution:
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Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{COCH}_3$
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