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2 gm of metal carbonate is neutralized completely by \(100 \mathrm{ml}\) of \(0.1(\mathrm{~N}) \mathrm{HCl}\). The equivalent weight of metal carbonate is
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200
Hints: Number of gram equivalents of \(\mathrm{HCl}\)
\(=\frac{100 \times 0.1}{1000}=0.01\)
Number of gram equivalents of metal carbonate required for neutralisation must also be 0.01 . Thus, mass of 1 gram eqivalent of carbonate salt \(\frac{2}{0.01}=200 \mathrm{~g}\)
\(\therefore\) Equivalent mass of carbonate salt \(=200\)
\(=\frac{100 \times 0.1}{1000}=0.01\)
Number of gram equivalents of metal carbonate required for neutralisation must also be 0.01 . Thus, mass of 1 gram eqivalent of carbonate salt \(\frac{2}{0.01}=200 \mathrm{~g}\)
\(\therefore\) Equivalent mass of carbonate salt \(=200\)
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