20.8 g of B a C l 2 on reaction with 9.8 g of H 2 S O 4 produces 7.3 g of H C l and some amount of B a S O 4 . The amount of B a S O 4 formed is

Question

20.8 g of B a C l 2 on reaction with 9.8 g of H 2 S O 4 produces 7.3 g of H C l and some amount of B a S O 4 . The amount of B a S O 4 formed is, 23.3 g, 20.8 g, 9.8 g, 10.4 g

MARKS App · Accepted Answer

According to law of conservation of mass Mass of reactants = Mass of products 20.8 + 9.8 = 7.3 + M a s s o f B a S O 4 ∴ Mass of B a S O 4 = 23.3 g

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