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29.2 % w/w HCl stock solution has a density of 1.25 g mL-1 . The molecular weight of HCl is 36.5 g mol-1 . The volume (mL) of stock solution required to prepare a 200 mL solution of 0.4 M HCl is
ChemistrySome Basic Concepts of ChemistryJEE Main
Solution:
2110 Upvotes Verified Answer
The correct answer is: 8
Density of HCl=1.25 g mL solution -1

Weight of 100 mL solution = 125 g

For a 29.2 % w/w HCl solution, weight =125100×29.2=36.5 gm

So in 100 mL solution, moles of HCl =36.536.5=1 moles

So molarity of HCl=10 M

Using M1V1=M2V2

Volume required =V2×10=200×0.4

V2=8 mL

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