3. C 0 + 7 ⋅ C 1 + 11 ⋅ C 2 + … + ( 3 + 4 n ) C n =

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Question: Answered & Verified by Expert

$3.C_0+7 \cdot C_1+11 \cdot C_2+\ldots+(3+4 n) C_n=$

MathematicsBinomial TheoremAP EAMCETAP EAMCET 2017 (25 Apr Shift 1)

Options:

A $(2 n+3) 2^n$
B $(2 n+1) 2^{n-1}$
C $(2 n+3) 2^{n-1}$
D $(2 n+1) 2^n$

Solution:

1608 Upvotes Verified Answer

The correct answer is: $(2 n+3) 2^n$

No solution. Refer to answer key.

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