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Question: Answered & Verified by Expert
3 g of acetic acid is added to 250 mL of 0.1 M HCl and the solution made up to 500 mL. To 20 mL of this solution 12 mL of 5 M NaOH is added. The pH of the solution is?
[Given: pKa of acetic acid =4.75 , molar mass of acetic acid =60 g/mol,log3=0.4771 ] Neglect any changes in volume.
ChemistryIonic EquilibriumNEET
Options:
  • A 2.61
  • B 4.52
  • C 5.22
  • D 8.78
Solution:
2715 Upvotes Verified Answer
The correct answer is: 5.22
mili mole of acetic acid in 20 ml =2
mili mole of HCl in 20 ml =1
mili mole of NaOH 20 ml =2.5
NaOH(left)1.50+CH3COOH20.5CH3COONa01.5+H2O0
pH=pKa+logsaltacid=4.74+log1.50.5
=4.74+log3=4.74+0.4771=5.22

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