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Question: Answered & Verified by Expert
30 mL of 0.1 M BaCl2 is mixed with 40 mL of 0.2 MAl2SO43 . What is the weight of BaSO4 formed ? BaCl2  +Al2SO43 BaSO4 + AlCl3  [Molecular Mass of BaSO4 = 233]
ChemistrySome Basic Concepts of ChemistryNEET
Options:
  • A 0.999 g
  • B 0.699 g
  • C 0.799 g
  • D 0.99 g
Solution:
1662 Upvotes Verified Answer
The correct answer is: 0.699 g
First balance it 3 BaCl 2 + Al 2 SO 4 3 3 BaSO 4 + 2 AlCl 3 mM before reaction 3 0 × 0 . 1 4 0 × 0 . 2 = 3 = 8 0 0 mM after reaction 0 8 - 1 3 2

   3 mM of BaCl2 reacts with one mole of Al2SO43 .

   mM of BaSO4 formed = 3 =wt.mol wt.×1000;

  wt. of BaSO4 formed =3 ×2331000= 0.699 g
 

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