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$34.2 \mathrm{~g}$ of cane sugar is dissolved in $180 \mathrm{~g}$ of water. The relative lowering of vapour pressure will he
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Verified Answer
The correct answer is:
$0.0099$
$\frac{p^{\circ}-p_{S}}{p^{\circ}}=\frac{\frac{w_{2}}{m_{2}}}{\frac{w_{1}}{m_{1}}+\frac{w_{2}}{M_{2}}}$
$=\frac{\frac{34.2}{342}}{\frac{34.2}{342}+\frac{180}{18}}$
$=\frac{0.1}{10.1}$
$=0.0099$
$=\frac{\frac{34.2}{342}}{\frac{34.2}{342}+\frac{180}{18}}$
$=\frac{0.1}{10.1}$
$=0.0099$
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