4 ml of H C l solution of p H = 2 is mixed with 6 m l of N a O H solution of p H = 12 . What would be the final p H of solution? l o g 2 = 0.3

Question

4 ml of H C l solution of p H = 2 is mixed with 6 m l of N a O H solution of p H = 12 . What would be the final p H of solution? l o g 2 = 0.3, 10.3, 11.3, 11, 4.3

MARKS App · Accepted Answer

[ H C l ] = 0.01 [ N a O H ] = 0.01 M m i x t = 6 × 0.01 - 4 × 0.01 10 = 0.02 10 [ O Θ H ] = 0.002 pOH = − log ( 0.002 ) = 2.7

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