Download MARKS App - Trusted by 15,00,000+ IIT JEE & NEET aspirants! Download Now
Search any question & find its solution
Question: Answered & Verified by Expert
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV=28 J K-1, calculate U and pV for the process. (R=8.0 J K-1 mol-1)
ChemistryThermodynamics (C)JEE MainJEE Main 2019 (08 Apr Shift 2)
Options:
  • A U=14 J; pV=0.8 J
  • B U=14 kJ; pV=18 kJ
  • C U=14 kJ; pV=4 kJ
  • D U=2.8 kJ; pV=0.8 kJ
Solution:
2602 Upvotes Verified Answer
The correct answer is: U=14 kJ; pV=4 kJ
ΔU=nCVΔT
=5×28×100=14000J
=14kJ
Δ(PV)=nRΔT=5×8×100=4000J=4kJ

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.