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50 g ice at $0^{\circ} \mathrm{C}$ in insulator vessel, 50 g water of $100^{\circ} \mathrm{C}$ is mixed in it, then final temperature of the mixture is (neglect the heat loss)
PhysicsThermal Properties of MatterJIPMERJIPMER 2014
Options:
  • A $10^{\circ} \mathrm{C}$
  • B $0^{\circ}\lt \lt T_m \lt 20^{\circ} \mathrm{C}$
  • C $20^{\circ} \mathrm{C}$
  • D above $20^{\circ} \mathrm{C}$
Solution:
2832 Upvotes Verified Answer
The correct answer is: $10^{\circ} \mathrm{C}$
According to calorimeter principle,
Heat given $=$ Heat taken
$m_1 s_1(100-t)=m L+m_2 s_2(t-0)$
$\begin{aligned} 50 \times 1(100-t) & =50 \times 80+50 \times 1(t-0) \\ t & =10^{\circ} \mathrm{C}\end{aligned}$

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