50 g ice at 0 ° C in kept in an insulating vessel and 50 g water at 100 ° C is mixed in it. Then the final temperature of the mixture is (neglect the heat loss)

Question

50 g ice at 0 ° C in kept in an insulating vessel and 50 g water at 100 ° C is mixed in it. Then the final temperature of the mixture is (neglect the heat loss), 10 ° C, 0 ° C T m 20 ° C, 20 ° C, above 20 ° C

MARKS App · Accepted Answer

Heat taken = Heat given m i L f + m i s w t - 0 = m w s w t n - t 50 × 80 + 50 × 1 × t = 50 × 1 × 100 - t 4000 = 50 100 - 2 t 80 = 100 - 2 t 2 t = 100 - 80 2 t = 20 t = 10 ° C

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