500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml of C O 2 and 3 litres of water vapour, all the volumes being measured at the same temperature and pressure. The formula of hydrocarbon is

Question

500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml of C O 2 and 3 litres of water vapour, all the volumes being measured at the same temperature and pressure. The formula of hydrocarbon is, C 4 H 10, C 5 H 12, C 2 H 2, C 5 H 10

MARKS App · Accepted Answer

Suppose the formula of hydrocarbon = C x H y x = v o l u m e o f C O 2 V o l u m e o f h y d r o c a r b o n = 2500 500 = 5 C x H y 1 v o l . 500 m l + x + y 4 O 2 = x C O 2 x v o l . 500 x m l + y 2 H 2 O y 2 v o l . 500 y 2 m l 500 y 2 = 3000 So y = 12 Molecular formula of hydrocarbon = C 5 H 12 .

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