Download MARKS App - Trusted by 15,00,000+ IIT JEE & NEET aspirants! Download Now
Search any question & find its solution
Question: Answered & Verified by Expert
500 ml of a hydrocarbon gas burnt in excess of oxygen yields 2500 ml of CO2 and 3 litres of water vapour, all the volumes being measured at the same temperature and pressure. The formula of hydrocarbon is
ChemistrySome Basic Concepts of ChemistryNEET
Options:
  • A C4H10
  • B C5H12
  • C C2H2
  • D C5H10
Solution:
2910 Upvotes Verified Answer
The correct answer is: C5H12
Suppose the formula of hydrocarbon =CxHy
x=volumoCOVolumohydrocarbon=2500500=5
CxHyvol.500 ml+x+y4O2=xCO2vol.500 xml+y2H2Oyvol.500yml
500y2=3000
So y = 12
Molecular formula of hydrocarbon =C5H12 .

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.