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$6 \mu C$ charge is placed at the centre of a cube. What will be the electric flux at each face of the tube?
$$
\left[\text { Take } \frac{1}{4 \pi \epsilon_o}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right]
$$
Options:
$$
\left[\text { Take } \frac{1}{4 \pi \epsilon_o}=9 \times 10^9 \mathrm{Nm}^2 \mathrm{C}^{-2}\right]
$$
Solution:
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Verified Answer
The correct answer is:
$36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}$
$\begin{aligned} & \left.\phi_{\text {net }}\right|_{\text {side }}=\frac{q_{\text {net }}}{6 \epsilon_0} \\ & =\frac{6 \times 10^{-6}}{6 \times 8.85 \times 10^{-12}} \\ & =112994.35 \\ & \simeq 36 \pi \times 10^3 \mathrm{Nm}^2 / \mathrm{C}\end{aligned}$
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