$ 64 \mathrm{~g} $ non-volatile solute is added to $ 702 \mathrm{~g} $ benzene. The vapour pressure of benzene has decreased from $ 200 \mathrm{~mm} $ of $ \mathrm{Hg} $ to $ 180 \mathrm{~mm} $ of $ \mathrm{Hg} $. Molecular weight of the solute is

Question

$ 64 \mathrm{~g} $ non-volatile solute is added to $ 702 \mathrm{~g} $ benzene. The vapour pressure of benzene has decreased from $ 200 \mathrm{~mm} $ of $ \mathrm{Hg} $ to $ 180 \mathrm{~mm} $ of $ \mathrm{Hg} $. Molecular weight of the solute is, $ 128 $, $ 64 $, $ 96 $, $ 256 $

MARKS App · Accepted Answer

V . P . has decreased by 10 % This happens only when 9 m o l e s solvent & one mole solute are present 702 g benzene = 9 m o l e s 64 g = 1 m o l e

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