Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
\( 7.6 \mathrm{gm} \mathrm{KBr} \) in \( 1250 \mathrm{ml} \) solution was found to have an osmotic pressure of \( 1.804 \) atm at \( 27^{\circ} \mathrm{C} \). Calculate degree of
dissociation in \( \% \) (Atomic weight \( \mathrm{K}=39, \mathrm{Br}=80 \) )
ChemistrySolutionsJEE Main
Options:
  • A \( 43.4 \% \)
  • B \( 58.4 \% \)
  • C 4. \( 64 \% \)
  • D \( 80 \% \)
Solution:
1272 Upvotes Verified Answer
The correct answer is: \( 43.4 \% \)

KBrK++Br-1          0       01-α     α       α     (1+α)

π=iCRT

i=1.804CRT  C=7.6119/12501000

=1.804×119×12507.6×1000×0.0821×300

i=1.434

i=1+α1

 α=i-1=1.434-1

α=0.434, %=43.4

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.