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\(9.3 \mathrm{~g}\) of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100\% yield/conversion) is _______ g. (nearest integer)
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The correct answer is:
20
Reaction suggests that 1 mole of aniline give 1 mole of orange dye.
$\begin{aligned}
& \text { so }(\mathrm{mol})_{\text {aniline }}=(\mathrm{mole})_{\text {orange dye }} \\
& \frac{9.3 \mathrm{~g}}{93 \mathrm{~g} \mathrm{~mol}^{-1}}=\frac{\text { mass of orange dye }}{199 \mathrm{~g} \mathrm{~mol}^{-1}}
\end{aligned}$
mass of orange dye $=19.9 \mathrm{~g} \simeq 20 \mathrm{~g}$
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