A 1 kg block attached to a spring vibrates with a frequency of 1 Hz on a frictionless horizontal table. Two springs identical to the original spring are attached in parallel to a 8 kg block placed on the same table. So, the frequency of vibration of the 8 kg block is

Question

A 1 kg block attached to a spring vibrates with a frequency of 1 Hz on a frictionless horizontal table. Two springs identical to the original spring are attached in parallel to a 8 kg block placed on the same table. So, the frequency of vibration of the 8 kg block is, 2 Hz, 1 4 Hz, 1 2 2 Hz, 1 2 Hz

MARKS App · Accepted Answer

The frequency of 1 kg block is f = 1 2 π k m = 1 Hz 4 π 2 = k m , m = 1 Spring constant, k = 4 π 2 In parallel connection of springs, the equivalent spring constant is k eq = 2 k . f = 1 2 π K × 2 8 Frequency of 8 kg block is = 1 2 Hz

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