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Question: Answered & Verified by Expert
A 10μF capacitor and a 20μF capacitor are connected in series across a 200 V supply line. The charged capacitors are then disconnected from the line and reconnected such that those same polarities are connected to each other and no external voltage is applied. The potential difference across capacitors is
PhysicsElectrostaticsJEE Main
Options:
  • A 4009V
  • B 8003V
  • C 400 V
  • D 200 V
Solution:
1618 Upvotes Verified Answer
The correct answer is: 4009V
 Cs=10×2010+20=20030=203 μF

 Q =CsV

 Q =203 μF×200 V

 Q =40003 μC

Now,  V = 4000 μC3×30 μF=400090 V=4009 V

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