A 10 μF capacitor is fully charged to a potential difference of 50 V After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V . The capacitance of the second capacitor is :

Question

A 10 μF capacitor is fully charged to a potential difference of 50 V After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V . The capacitance of the second capacitor is :, 15 μF, 30 μF, 20 μF, 10 μF

MARKS App · Accepted Answer

V = C 1 V 1 + C 2 V 2 C 1 + C 2 20 = 10 × 50 + 0 20 + C C = 15 μ F

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