A 10 g bullet moving directly upward at 1000 m s - 1 strikes and passes through the centre of mass of a 10 kg block initially at rest. The bullet emerges from the block moving directly upward at 400 m s - 1 . What will be the velocity of the block just after the bullet comes out of it?

Question

A 10 g bullet moving directly upward at 1000 m s - 1 strikes and passes through the centre of mass of a 10 kg block initially at rest. The bullet emerges from the block moving directly upward at 400 m s - 1 . What will be the velocity of the block just after the bullet comes out of it?, 1 m s - 1, 0.4 m s - 1, 1.4 m s - 1, 0.6 m s - 1

MARKS App · Accepted Answer

Given, Weight of bullet m B = 10 g = 10 × 10 - 3 k g Weight of block M = 10 k g The initial velocity of the bullet v i = 1000 m s - 1 The final velocity of the bullet v f = 400 m s - 1 By the law of conservation of momentum, m B v i = m B v f + 10 v [ w h e r e , v = v e l o c i t y o f b l o c k ] 10 × 10 - 3 1000 = 10 × 10 - 3 400 + 10 v 10 = 4 + 10 v 10 v = 10 - 4 v = 6 10 = 0. 6 m s - 1

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