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A 10 kg stone is suspended with a rope of breaking strength 30 kg-wt. The minimum time in which the stone can be raised through a height 10 m starting from rest is
(Taking g = 10 m/s2)
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(Taking g = 10 m/s2)
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Verified Answer
The correct answer is:
Maximum tension in the string T = mg
= 30 x 10
= 300 N
T - mg = ma
From the figure
300 - 10 x 10 = 10a
a = 20 m s-2
Thus, the maximum acceleration with which the stone can be raised is 20 m s-2.
Given, s = 10 m
and u = 0
t = 1 s
= 30 x 10
= 300 N
T - mg = ma
From the figure
300 - 10 x 10 = 10a
a = 20 m s-2
Thus, the maximum acceleration with which the stone can be raised is 20 m s-2.
Given, s = 10 m
and u = 0
t = 1 s
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