Search any question & find its solution
Question:
Answered & Verified by Expert
A $10 \mathrm{~kW}$ transmitter emits radio waves of wavelength $500 \mathrm{~m}$. The number of photons emitted per second by the transmitter is of the order of
Options:
Solution:
1382 Upvotes
Verified Answer
The correct answer is:
$10^{31}$
$10^{31}$
Power $=\frac{n h c}{\lambda}$
(where, $n=$ no. of photons per second)
$$
\Rightarrow \quad n=\frac{10 \times 10^3 \times 500}{6.6 \times 10^{-34} \times 3 \times 10^8} \simeq 10^{31}
$$
(where, $n=$ no. of photons per second)
$$
\Rightarrow \quad n=\frac{10 \times 10^3 \times 500}{6.6 \times 10^{-34} \times 3 \times 10^8} \simeq 10^{31}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.