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Question: Answered & Verified by Expert
A $10 \mathrm{~kW}$ transmitter emits radio waves of wavelength $500 \mathrm{~m}$. The number of photons emitted per second by the transmitter is of the order of
PhysicsCommunication SystemJEE MainJEE Main 2012 (12 May Online)
Options:
  • A
    $10^{37}$
  • B
    $10^{31}$
  • C
    $10^{25}$
  • D
    $10^{43}$
Solution:
1382 Upvotes Verified Answer
The correct answer is:
$10^{31}$
Power $=\frac{n h c}{\lambda}$
(where, $n=$ no. of photons per second)
$$
\Rightarrow \quad n=\frac{10 \times 10^3 \times 500}{6.6 \times 10^{-34} \times 3 \times 10^8} \simeq 10^{31}
$$

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