Search any question & find its solution
Question:
Answered & Verified by Expert
A $10 \mathrm{ohm}$ resistance, $5 \mathrm{mH}$ coil and $10 \mu \mathrm{F}$ capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency
Options:
Solution:
2864 Upvotes
Verified Answer
The correct answer is:
Remains unchanged
At resonance, \(\mathrm{f}=\frac{1}{2 \pi \sqrt{\mathrm{LC}}}\)
Hence no effect of \(R\). The resonance frequency remains same when \(R\) is changed.
Hence no effect of \(R\). The resonance frequency remains same when \(R\) is changed.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.