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Question: Answered & Verified by Expert
A $10 \mathrm{ohm}$ resistance, $5 \mathrm{mH}$ coil and $10 \mu \mathrm{F}$ capacitor are joined in series. When a suitable frequency alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency
PhysicsAlternating CurrentJEE Main
Options:
  • A Is halved
  • B Is doubled
  • C Remains unchanged
  • D In quadrupled
Solution:
2864 Upvotes Verified Answer
The correct answer is: Remains unchanged
At resonance, \(\mathrm{f}=\frac{1}{2 \pi \sqrt{\mathrm{LC}}}\)
Hence no effect of \(R\). The resonance frequency remains same when \(R\) is changed.

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