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A 2 V battery, a $15 \Omega$ resistor and a potentiometer of $100 \mathrm{~cm}$ length, all are connected in series. If the resistance of potentiometer wire is $5 \Omega$, then the potential gradient of the potentiometer wire, is
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The correct answer is:
$0.005 \mathrm{~V} / \mathrm{cm}$
Potential gradient $\frac{d v}{d x}=\frac{e}{\left(R+R_{h}+r\right)} \cdot \frac{R}{L}$
$$
\begin{array}{l}
=\frac{2}{(15+5+0)} \times \frac{5}{1}=0.5 \mathrm{~V} / \mathrm{m} \\
=0.005 \mathrm{~V} / \mathrm{cm}
\end{array}
$$
$$
\begin{array}{l}
=\frac{2}{(15+5+0)} \times \frac{5}{1}=0.5 \mathrm{~V} / \mathrm{m} \\
=0.005 \mathrm{~V} / \mathrm{cm}
\end{array}
$$
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