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$\vec{a}=3 \hat{i}-5 \hat{j}$ and $\vec{b}=6 \hat{i}+3 \hat{j}$ are two vectors and $\vec{c}$ is a vector such that $\vec{c}=\vec{a} \times \vec{b}$ then
$$
|\vec{a}|:|\vec{b}|:|\vec{c}|
$$
Options:
$$
|\vec{a}|:|\vec{b}|:|\vec{c}|
$$
Solution:
1401 Upvotes
Verified Answer
The correct answer is:
$\sqrt{34}: \sqrt{45}: 39$
$\sqrt{34}: \sqrt{45}: 39$
We have $\vec{a} \times \vec{b}=39 \vec{k}=\vec{c}$
Also $|\vec{a}|=\sqrt{34},|\vec{b}|=\sqrt{45},|\vec{c}|=39 \therefore \quad|\vec{a}|:|\vec{b}|:|\vec{c}|=\sqrt{34}: \sqrt{45}: 39$
Also $|\vec{a}|=\sqrt{34},|\vec{b}|=\sqrt{45},|\vec{c}|=39 \therefore \quad|\vec{a}|:|\vec{b}|:|\vec{c}|=\sqrt{34}: \sqrt{45}: 39$
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