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Question: Answered & Verified by Expert
a=4i^+13j^18k^,b=i^2j^+3k^ and c=2i^+3j^4k^ are three vectors such that a=xb+yc, then x+y=
MathematicsVector AlgebraMHT CETMHT CET 2021 (23 Sep Shift 1)
Options:
  • A -1
  • B -2
  • C 5
  • D 1
Solution:
1421 Upvotes Verified Answer
The correct answer is: 1
a=xb+yc4i^+13j^18k^=(i^2j^+3k^)(x)+(2i^+3j^4k^)(y)=(x+2y)i^+(2x+3y)j^+(3x4y)k^x+2y=4,2x+3y=13 and 3x4y=18
Solving, we get x=2,y=3x+y=1

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