Download MARKS App - Trusted by 15,00,000+ IIT JEE & NEET aspirants! Download Now
Search any question & find its solution
Question: Answered & Verified by Expert
A 40 μF capacitor is connected to a 200 V, 50 Hz AC supply. The rms value of the current in the circuit is, nearly:
PhysicsAlternating CurrentNEETNEET 2020 (Phase 1)
Options:
  • A 2.05 A
  • B 2.5 A
  • C 25.1 A
  • D 1.7 A
Solution:
2870 Upvotes Verified Answer
The correct answer is: 2.5 A

Current flowing through the capacitor is given by,Irms=VXC=V1/Cω=VCω

Irms=200×40×106×2π×50

Irms=2.5 A

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.